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Old 09-30-2003, 11:20 AM   #1 (permalink)
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Quick question - centre of gravity/mass

Hi there,

How do I calculate the centre of gravity/mass of a 2m long bar that varies from 10kg/m at the left hand end to 5kg/m at the right hand end?

Thanks
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Old 09-30-2003, 11:24 AM   #2 (permalink)
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Homework time again? Looks like the school year has started.
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Old 09-30-2003, 11:46 AM   #3 (permalink)
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Quote:
Originally posted by redlemon
Homework time again? Looks like the school year has started.
Yeah - seems like Tilted Knowledge has suddenly become Tilted Help Me With My Homework.

Edit: Okay - as per <b>Halx</b>, "The Tilted Knowledge forum is basically a place for you to ask for secular knowledge such as mathematics and grammar."

Therefore, I will withdraw my comment, and change it to:
"Read the damn textbook."
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Last edited by yournamehere; 09-30-2003 at 12:38 PM..
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Old 09-30-2003, 01:15 PM   #4 (permalink)
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Quote:
Originally posted by yournamehere
[BEdit: Okay - as per <b>Halx</b>, "The Tilted Knowledge forum is basically a place for you to ask for secular knowledge such as mathematics and grammar."[/B]
D'OH!

OK, I'll be polite as well then.

If you have lost your textbook, you can do it through geometry, changing "mass" to "area". Basically, you end up with a triangle; figure out where the line is that gives you equal area on each side.
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Old 09-30-2003, 01:17 PM   #5 (permalink)
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Does it change uniformly along its length?
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Old 10-01-2003, 01:40 AM   #6 (permalink)
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Quote:
Originally posted by cliche
Does it change uniformly along its length?
Yeah, sorry should've said.

Thanks for the tips guys, problem is, this is a set of questions I have been given to prepare me for my University course, and I'm not at University yet so I don't have any of the textbooks.
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Old 10-01-2003, 02:47 AM   #7 (permalink)
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Well, if you Google using "center" instead of "centre", this NASA page is pretty cool. Again, convert "mass" to "area".
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Old 10-01-2003, 01:58 PM   #8 (permalink)
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OK thats great, I managed to do it using the area idea. Thanks again.
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