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		#2 (permalink) | |
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			 Location: Waterloo, Ontario 
				
				
				
				
				
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		 Quote: 
	
 The correct method of isolation will be so simple that you'll wonder why you didn't see it, yourself. Try doing this: Code: 
	1/a + 1/b = 1 1/a = 1 - 1/b (isolate the term with the wanted variable) a = 1/(1 - 1/b) (reciprocate both sides) The first two should be obvious. Neither a nor b may be zero, since division by zero is undefined. The third provision may come as a surprise but (1 - 1/b) may not be zero, either, since we divide by it. In other words, b ≠ 1. You can even see that this must be so because, in the original equation, if b were one, then the reciprocal of a must be zero, which is pretty hard to do (mild understatement)...  | 
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		#3 (permalink) | 
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			 “Wrong is right.” 
			
			
			
			
				
			
			Location: toronto 
				
				
				
				
				
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		 OF COURSE the answer ends up coming from Waterloo, Ontario....  
		
		
		
		
		
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		#4 (permalink) | 
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			 Insane 
			
			
			
			
				
			
			Location: Kansas City, MO 
				
				
				
				
				
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		 Yeah, I feel kind of silly after actually sitting down and putting some effort into it. I reallized I had thought way to much about it. 
		
		
		
		
		
			1/a + 1/b = 1 ab(1/a) + ab(1/b) = ab b + a = ab b/a + a/a = ab/a b/a + 1 = b b/a = b - 1 b = a(b - 1) a = b/(b - 1) Although, I admit that you solution was much easier and more intuitive. Thank you kindly for your insight. Herk 
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| Tags | 
| easy, math, question, seemingly | 
		
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