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Old 10-20-2004, 07:44 PM   #1 (permalink)
Junkie
 
C++ double error

What does the it mean when a double outputs as these error codes?

-1.#J
-1.#IND
Rekna is offline  
Old 10-20-2004, 10:07 PM   #2 (permalink)
Crazy
 
Location: here and there
-1.#IND is NaN (not a number) sqrt(-1), 0.0f / 0.0f will both give this result.

not sure about the other.
theFez is offline  
Old 10-22-2004, 02:07 AM   #3 (permalink)
Upright
 
Location: Berkeley, CA
Never seen -1.#J before. Looks interesting. Are you going to tell us how you got that value?
littlebighead is offline  
Old 10-22-2004, 11:42 PM   #4 (permalink)
Junkie
 
the -1.#IND was comming from the square root of a negative. I have no clue what caused the -1.#J I'm running some linear algerbra algorithms on some large matrix's to demonstrate floating point errors. So it is probably realted to that somehow.
Rekna is offline  
 

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